Question 292138
Simplify:
{{{5/(2-i)}}} To simplify, you multiply top and bottom by the conjugate of {{{2-i}}} which is {{{2+i}}}
{{{5(2+i)/(2-i)(2+i)}}} Simplify.
{{{5(2+1)/(4-i^2)}}} Substitute {{{i^2 = -1}}}
{{{5(2+i)/(4-(-1))}}}
{{{5(2+i)/(4+1)}}}
{{{cross(5)(2+i)/cross(5)}}} Cancel the 5's as indicated to leave you with:
{{{highlight(2+i)}}}