<PRE><B>Question 291689</B>
A ball is projected into the air. Its height at time t is given by the equation h = -16t^2 + 60x +1. When will the height be 8 feet?
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When h = 8
8 = -16t^2 + 60t + 1  (I think you meant 60t, not 60x)
-16t^ + 60t - 7 = 0
*[invoke solve_quadratic_equation -16,60,-7]
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x1 and x2 are the values of t.
There are 2 of them, 8 feet going up, and 8 feet coming back down.

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