Question 291569
Because 10% of the reservation holders are 'no shows' a Canadian airline sells 400 tickets for a flight that can accommodate 375 passengers. 
a) Find the probability that one or more reservation holders will not be accomodated on the flight.
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Binomial Problem with n = 400, p = 0.1
P(x>375) = 1 - P(0<= x <=374) = 1 - 400C374(0.9)^374*(0.1)^26 = 0.0054...
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b) Find the probability of fewer than 350 passengers on the flight.
P(0<= x <=349) = 0.0436..
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Cheers,
Stan H.