<PRE><B>Question 291236</B>
You mean the sum of the die will be seven.
Look at all of the possible outcomes and their sums. 
There are 36 total. 
1	1	2
1	2	3
1	3	4
1	4	5
1	5	6
1	6	7
2	1	3
2	2	4
2	3	5
2	4	6
2	5	7
2	6	8
3	1	4
3	2	5
3	3	6
3	4	7
3	5	8
3	6	9
4	1	5
4	2	6
4	3	7
4	4	8
4	5	9
4	6	10
5	1	6
5	2	7
5	3	8
5	4	9
5	5	10
5	6	11
6	1	7
6	2	8
6	3	9
6	4	10
6	5	11
6	6	12
If you add them up, 6 of the 36 sums add up to 7.
P(7)={{{6/36=1/6}}}
Of the remaining 30 outcomes, 15 of the sums are less than 7, 15 are greater than 7.
P(&lt;7)={{{15/36=5/12}}}
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