Question 4554
Is this what you mean?  {{{log (b, (v^7/u^8)) }}}


If so, then use the laws of logarithms {{{log (M/N) = log M - log N }}} to write this as separate but simpler logs:
{{{log (b, (v^7)) - log (b, (u^8)) }}}


This can further be broken down using the third law of logs: {{{log M^N = N * log M}}}:


{{{7 * log (b, v) - 8 * log (b, u) }}}


R^2 from SCC