Question 290789
Rodgers age is 1 and 1/3 times Stevens age.
r = {{{4/3}}}s
multiply by 3
3r = 4s
4s = 3r
s = {{{3/4}}}r
:
Eight years ago, Rodger's age was twice Steven's age.
r - 8 = 2(s-8)
r - 8 = 2s - 16
r = 2s - 16 + 8
r = 2s - 8
:
Find Rodger's age
:
Replace s with {{{3/4}}}r in the above equation
r = 2({{{3/4}}}r) - 8
r = {{{6/4}}}r - 8
Multiply equation by 4, results
4r = 6r - 32
32 = 6r - 4r
32 = 2r
r = {{{32/2}}}
r = 16 yrs is Roger's age
:
:
Check solution:
s = {{{3/4}}}(16)
s = 12
"Eight years ago, Rodger's age was twice Steven's age."
16 - 8 = 2(12-8)
8 = 2(4)