Question 290739
2x^2-3x-35=0
Factoring, we get:
2x^2 -10x +7x -35 =0
(2x^2 -10x) + (7x -35) =0
2x(x-5) + 7(x-5) =0
(x-5)(2x+7) = 0
x = {-7/2, 5}