Question 290651
OK our two equations are:

1) 5x - 4y = -7  and
2) x - 3y/5 = -2

In substitution you need one of the equations to equal a single variable..in this case equation 2 is easiest to do that

So:  x - 3y/5 = -2  add 3y/5 to both sides

x = 3y/5 - 2   Now you know what x equals and you can substitute it into equation 1

Hence:

5(3y/5 - 2) - 4y = -7  now solve it...
15y/5 - 10 - 4y = -7
3y - 10 - 4y = -7  add 10 to both sides
3y - 4y = 3  subtract the y's
- y = 3  and multiple both sides by -1...you cannot have a negative y 
y = -3

Now use y = -3 in your original equation and solve for x

Use equation 1

5x - 4(-3) = -7
5x + 12 = -7  subtract 12 from both sides
5x = -19  divide by 5
x = -19/5  

so (-19/5, -3) are your cordinates..to check plug in numbers to both equation 1 and 2 then solve...this cordinate should work in both.