Question 290554
Let x, x+2 & x+4 be the 3 consecutive odd numbers.
x(x+2)=(x+4)^2-28
x^2+2x=x^2+8x+16-28
x^2-x^2+2x-8x=16-28
-6x=-12
x=-12/-6
x=2 ans.
Proof:
2(2+2)=(2+4)^2-28
2*4=6^2-28
8=36-28
8=8