Question 290379
{{{((x^2-25)/(x^2-3x-10))*((x-2)/(x))}}}
When multiplying fractions, it is usually best to cancel factors common to the numerator and denominator before actually multiplying. So we'll start by factoring to see if anything will cancel:
{{{(((x+5)(x-5))/((x+2)(x-5)))*((x-2)/x)}}}
As we can see, the (x-5)'s will cancel:
{{{(((x+5)cross((x-5)))/((x+2)cross((x-5))))*((x-2)/x))}}}
leaving:
{{{((x+5)/(x+2))*((x-2)/x)}}}
Now we can multiply much simpler expressions giving:
{{{(x^2+3x-10)/(x^2+2x)}}}