Question 290418
three consecutive integers whose product is 60
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1st: x-1
2nd: x
3rd: x+1
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Equation:
product = 60
(x-1)x(x+1) = 60
x(x^2-1) = 60
x^3-x-60 = 0
x = 4
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1st:3
2nd:4
3rd:5
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Cheers,
Stan H.
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