Question 34753
1/3[2ln(x+3) + lnx - ln(x^2-1)]
= 1/3 [ln(x+3)^2 + lnx - ln(x^2-1)]
= 1/3 ln[x(x+3)^2/(x^2-1]
= ln[x(x+3)^2/(x^2-1]^1/3