Question 290412
The pilot of an airplane flies at a constant speed of 200 km/h at a bearing of S 40° E. 
There is a 42 km/h crosswind blowing E 20° N. 
What are the plane’s actual speed and direction? Please show all appropriate steps and diagrams. 
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Plane DATA:
x vector = 200*cos(270+40) = 128.56
y vector = 200*sin(270+40) = -153.21
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Wind DATA:
x vector = 42*cos(20) = 39.47
y vector = 42*sin(20) = 14.37
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Conbining corresonding vectors:
x vector 128.56+39.47 = 168.03
y vector -153.21+14.37 = -138.84
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distance = sqrt(168.03^2 + 138.84^2) = 217.97 km
angle = arctan(-138.84/168.03) = -39.57 degrees
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Cheers,
Stan H.