Question 290274
Solve, using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{0.5x^2 = x+0.5}}} Subtract (x+0.5) from both sides.
{{{0.5x^2-x-0.5 = 0}}} a = 0.5, b = -1, and c = -0.5
{{{x = (-(-1)+-sqrt((-1)^2-4(0.5)(-0.5)))/2(0.5)}}}
{{{x = (1+-sqrt(1-4(-0.25)))/1}}}
{{{highlight(x = 1+-sqrt(2))}}}