Question 290239
{{{f(n)=(sin(n)-n)/n^3}}}
{{{f(n)=sin(n)/n^3-1/n^2}}}
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The sine function varies from [-1,1]
{{{lim( n->infinity, (sin(n)/n^3) )=0}}} 
{{{lim( n->infinity, (1/n^2) )=0}}} 
So then
{{{lim( n->infinity, ((sin(n)-n)/n^3) )=0}}}