Question 289988

Given:
<t>a = 2 </t>
<t>b = 5 
<t>c = (-3)<br>
Gives us:
<t>{{{ 3(2)^2 - 5 + 2(-3)}}} <br>
Following the <i>Order of Operations</i> (PEMDAS), since we have no operations <i>inside</i> parenthesis, we deal with the exponent first:
<t>{{{ 3(2)^2 - 5 + 2(-3) }}} becomes {{{ 3(4) - 5 + 2(-3) }}}<br>
Next, working from left to right, we do multiplication:
<t>{{{ 3(4) - 5 + 2(-3) }}} now becomes {{{ 12 - 5 + (-6) }}} or {{{ 12 - 5 - 6 }}}<br>
From {{{ 12 - 5 - 6 }}} I'll allow you to do the final two operations and bob's your uncle!