Question 286732
Your original equation was {{{x^2-5x=6}}}
Set the quadratic equation equal to zero before you factor!
Subtract 6 on both sides: {{{x^2-5x-6=0}}}
From here you can factor: (x-6)(x+1)=0
x-6=0 and x+1=0
x=6 and x=-1
X can be equal to 6 and -1.
We should check to make sure!
Plug in the values of 6 and -1 for x.

Plug in 6: {{{6^2-5(6)=6}}}
{{{36-30=6}}}
{{{6=6}}}
This works!

Plug in -1: {{{(-1)^2-5(-1)=6}}}
{{{1+5=6}}}
{{{6=6}}}
This works!

Answer: x is equal to 6 and -1. I hope this helps! :]