Question 289602
1.{{{x + y = 1}}}
2.{{{2x - 3y = 12}}}
Multiply eq. 1 by 3 and add to eq. 2 to solve for x.
{{{3x+3y+2x-3y=3+12}}}
{{{5x=15}}}
{{{highlight( x=3)}}}
Now use either eq. 1 or eq. 2 to solve for y.
{{{x+y=1}}}
{{{3+y=1}}}
{{{highlight( y=-2)}}}