Question 289568
(x+(1/8))^2=(x+(1/8))*(x+(1/8))
We use FOIL
that's four operations
first terms x*x=x^2
inner terms 1/8*x
outer terms x*1/8
last terms 1/8*1/8
x^2+(x/4)+(1/64)
the first and last are easy to see
the middle term x/4 is a sum of O and I operations
1/8*x+x*1/8=2/8*x=1/4*x