Question 289559
Note: All logs are assumed to be base 10.



Hint: Use the idea that {{{log((x))+log((y))=log((xy))}}} to get {{{log(((x-1)(x+2)))=1}}}. Now convert into exponential form to get {{{(x-1)(x+2)=10^1}}} and simplify to get {{{(x-1)(x+2)=10}}}. I'll let you take it from here.