<PRE><B>Question 289553</B>
Could someone please help me with this? 
Find the negative value of x such that 2^log4(1/64) + x^2 = (73/8). 
Thanks!

need to do this a piece at a time

first evaluating log4 (1/64)
4^r = 1/64
r = -3
leaves:
2^(-3) + x^2 = 73/8
1/8 + x^2 = 73/8
x^2 = 72/8 = 36/4 = 18/2 = 9
x = 3 or x = -3
the negative value of x is -3

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