Question 289505
{{{(2+i)/(1-3i)=((2+i)/(1-3i))*((1+3i)/(1+3i))}}}
{{{(2+i)/(1-3i)=(2+6i+i+3i^2)/(1+3i-3i-9i^2)}}}
{{{(2+i)/(1-3i)=(-1+7i)/(10)}}}