Question 289358
Set the equations equal to each other, because y=y.
{{{ x+2 }}} = {{{ x^2 }}}

Minus {{{ x+2 }}} on both sides, so you get {{{ x^2-x-2 }}} =0
The factors are: (x-2) (x+1)=0
x-2=0 and x+1=0
x=2 and x=-1