Question 289357
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Very carefully, and with great attention to detail.


Since you have two expressions that are both equal to *[tex \Large y], set them equal to each other.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ =\ x\ +\ 2]


A little algebra:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ x\ -\ 2\ =\ 0]


Factor and solve the quadratic for the two values of *[tex \Large x] then substitute each into either of the original equations to derive the corresponding value of *[tex \Large y].  Express your answer as a set of ordered pairs.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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