Question 289411
[(x-2)/(x-8)]-[1/x] = [(x-7)/x]
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Multiply thru by x(x-8) to get rid of the denominators:
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x(x-2) - (x-8) = (x-8)(x-7)
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x^2 - 2x -x + 8 = x^2-15x+56
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-3x + 8 = -15x + 56
12x = 48
x = 4
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Cheers,
Stan H.
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