Question 289247
I think the other tutor misread the problem.
3^(2-x^2)=8
3^2*3^(-x^2)=8
9*3^(-x^2)=8
1/(3^(x^2))=8/9
3^(x^2)=9/8
x=-sqrt((log(9/8))/(log(3)))
x=-0.327431
x=sqrt((log(9/8))/(log(3)))
x=0.327431
= your answer