Question 289365
The height of an object thrown in the air is given by h = t2 – 7t + 3, where h is in feet and t is the time in seconds the object has been in motion. At what time (to the nearest tenth) is the object 11 feet in the air?
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h is the height so make it 11 and solve for "t":
t^2-7t+3 = 11
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t^2 -7t -8 = 0
(t-8)(t+1) = 0
Positive solution:
t = 8 seconds (time at which the object is at a height of 11 ft.
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Cheers,
Stan H.