Question 4565
 Among "SUCCESS", there are 3 S, 2 C , 1 U & 1 E.
 
 So, there are 7!/(3! 2!) = (7*6*5*4)/2 = 420 possible arrangements
 
 When all 3 S come together , there are (1+2+1+1)!/2! = 5!/2! = 60

 Hence, there are 420-60 = 360 arrangements that all the S do not come together.

 Kenny