Question 289027
{{{f(x)=2x^2+11x-6}}} Start with the given function.



{{{0=2x^2+11x-6}}} Plug in {{{f(x)=0}}}



{{{2x^2+11x-6=0}}} Rearrange the equation.



Now let's use the quadratic formula to solve for 'x'.


*[invoke quadratic_formula 2,11,-6, "x"]



Since the solutions are {{{x=-6}}} or {{{x=1/2}}}, this means that the x-intercepts are *[Tex \LARGE \left(-6,0\right)] and *[Tex \LARGE \left(\frac{1}{2},0\right)]