Question 289073
Solve ( x^2 – 2x )( x + 3) = -2x ( x + 1)
 
This is what I have so far. 
x^3+3x^2-2x^2-6x=-2x^2-2x 
x^3+x^2-6x=-2x^2-2x 
x^3+x^2+2x^2-6x=-2x 
x^3+3x^2-4x=0
x(x^2+3x-4) = 0
x(x+4)(x-1) = 0
x = 0 or x = -4 or x = 1
==============================
cheers,
Stan H.