Question 288932
First step.
Multiply the entire equation by (y-1)(2y-2)
so you get 3(y-1)-2(2y-2)= -1/2(y-1)(2y-2)
second step.
simplify.
first foil the (y-1)(2y-2) = (2y^2)-4y-2
then you distribute the 3 the -2 and the -1/2
you get 3y-3-4y+4= (-y^2)+2y+1
now combine like terms
you get -y+1=(-y^2)+2y+1
now add y 
you get 1=(-y^2)+2y+1 
subtract 1
you get 0=(-y^2)+2y+0
now you can either use quadratic formula or foil
this is the quadratic formula. {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
A is -1, B is 2, and C is 0 just plug in and solve. 
this equation cannot be factored but after plugging in the numbers in the formula you shoud get the answers well youll get x = but it same as y= in this case. answer is y=0 and y=2 make sure to check your answers by plugging the final answers into the origional equation and in this case I did and found out that 2 is the only solution for 0 does not work.