Question 288795
This is a composition of functions problem.


I assume that f(x) should be written like this:

{{{f(x)=2^x-1}}}

and {{{g(x)=x^2-1}}}


(f o g)(3) means put x=3 into g(x), get a number, and then put that number into f(x)


Here's how it's done:

{{{g(3)=(3)^2-1}}}
{{{g(3)=8}}}


Now find f(8):


{{{f(8)=(2)^8 - 1}}}
{{{f(8)=256-1}}}
{{{f(8)=255}}}