Question 288732
If the Range is directly proportional to the square of the velocity, you can set up an equation like this:


{{{R=av^2}}}


where R=range, a=proportionality constant, and v=velocity


{{{140=a(60)^2}}}
{{{a=7/180}}}


Now use this value of a with the new information, that v=65mph to solve for R:


{{{R=(7/180)(65)^2}}}
{{{R=164.3}}}


The range would be 164.3 feet if the speed was increased to 65mph.


Hope this helps. Please let me know if you have any questions.