Question 288336
128^(2x-1)=(1/16)^(x+2)
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128 = 2^7 (if you don't know this, you should)
1/16 = 2^-4
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{{{2^(7*(2x-1)) = 2^(-4*(x+2))}}}
Since the bases are the same:
7(2x-1) = -4(x+2)
You can finish it.