Question 288295
then {{{(-4+-2sqrt(6))/(4)}}} (this is supposed to read "+ or - 2", not -2)
then after simplifying, I get
{{{(-1+-sqrt(6))/(2)}}} ****  This last step is not right ***
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My book says the answer is: {{{(-2+-sqrt(6))/(2)}}}
I can't figure out where I went wrong, so I can't answer my real question of 2x^2+10x-3=0.
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2x^2+10x-3=0
*[invoke solve_quadratic_equation 2,10,-3]
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= (-5 ± sqrt(31))/2