Question 288296
Problem: 2x^2+4x-1=0
Formula I used was: {{{(-4+-sqrt(4^2-4*2*-1))/(2*2)}}}
I got:
{{{(-4+-sqrt(16-4*2*-1))/(2*2)}}}
then {{{(-4+-sqrt(16+8))/(2*2)}}}
then {{{(-4+-sqrt(24))/(2*2)}}}
then {{{(-4+-2sqrt(6))/(2*2)}}} (this is supposed to read "+ or - 2" not -2)
then {{{(-4+-2sqrt(6))/(4)}}} (this is supposed to read "+ or - 2", not -2)
then after simplifying, I get
{{{(-1+-sqrt(6))/(2)}}}
My book says the answer is: {{{(-2+-sqrt(6))/(2)}}}
I can't figure out where I went wrong, so I can't answer my real question of 2x^2+10x-3=0.
Any help is appreciated!! Thank you!
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You did fine until the last step:
(-4+-2sqrt(6))/(4)
There is a common factor of 2 in the numerator 
and in the denominator.
Remove it and cancel it and you get:
(-2+sqrt(6))/2
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Cheers,
Stan H.