Question 288023
1. You have 6 bags of mulch, while 3 bags would cover 24 square feet. The area of the pumpkin patch would simply be the double of 24 square feet, or <b>48 square feet</b>.

2. Say that the square pumpkin patch has a side length of L. Since it's square-shaped, the length and width would be the same, which means that the area of the pumpkin patch would be:
{{{A = L x L = L^2}}}
{{{L=sqrt(48)}}}, which is around 6.92820323 feet. Rounded up to the nearest food, it would be <b>7 feet</b> (which is the square root of 49, close enough to 48).

3. I'll leave the drawing to you, it should be an easy enough work.

A diagonal of the pumpkin patch would "divide" the square patch into two triangles, becoming its <u>hypothenuse</u> (the longest line that a triangle has). Use the Pythagorean theorem to find its length (which equals the length of the path). Let's say that the length of the diagonal/hypothenuse is represented by D:

{{{D^2=L^2+L^2=2L^2}}}

{{{D=sqrt(2L^2)}}}, L is the square root of 48, so {{{L^2=48}}}

Back to D:

{{{D=sqrt(2*48)=sqrt(96)=4*sqrt(6)}}} which is roughly <b>9.79795897 feet</b> (around 10 feet).

4. First, convert feet into inches, then to centimetres. Using the conversion factor 1 ft = 12 in, 1 in = 2 cm:
{{{4*sqrt(6)}}}ft = {{{48*sqrt(6)}}} in = {{{96*sqrt(6)}}} cm, which is roughly <b>235.151015 cm</b>

Or if they want the amount in feet to be rounded up to 10 feet first...
10 ft = 120 in = <b>240 cm</b> (which would certainly make calculations for number 2 easier...)

5. If the path were 10 feet/240 cm long, the amount of paver stones required would simply be 240 cm divided by 2 cm, which is <b>120</b> stones.