Question 288222
The perimeter is (=) twice (two times) the sum of its length and width (L+W).  
P=2(L+W)

The perimeter is (=) 28 meters and its length is 2 meters more (+2) than twice (times 2) its width.  What is the length?
P=28
L=2+2W

So you know that P=28.  Plug that into the first equation:
P=2(L+W)
P=28
28=2(L+W)
then simplify by distributing
28=2L+2W
You also know that L=2+2W, so substitute that for L
28=2(2+2W)+2W
now distribute again
28=4+4W+2W
combine like terms
28=4+6W
subtract 4 from both sides
24=6W
divide by 6 on both sides
4=W
so we know that W=4, but the problem asks for the length, so plug 4 in for W in the equation for length at the top.
L=2+2(4)
L=2+8
L=10
Your answer is that the length of the rectangle is 10 meters (don't forget the unit is meters)