Question 288174


{{{-10x+6y=-30}}} Start with the given equation.



{{{6y=-30--10x}}} Add {{{10x}}} to both sides.



{{{6y=--10x-30}}} Rearrange the terms.



{{{y=(--10x-30)/(6)}}} Divide both sides by {{{6}}} to isolate y.



{{{y=((--10)/(6))x+(-30)/(6)}}} Break up the fraction.



{{{y=(5/3)x-5}}} Reduce.



So the equation {{{y=(5/3)x-5}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=5/3}}} and the y-intercept is {{{b=-5}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-5\right)]