Question 288114
It is fairly simple. You only need to recall the relation between the exponential number (e) and natural logarithm (ln). ln(x) is simply the inverse of the function e^x, which means that:

{{{e^(lnx)=x}}}

As with ordinary logarithm, {{{N*ln(x)=ln(x^N)}}}. For this situation, x = e and N = -1, yielding:

{{{e^(-ln(e))=e^(ln(e^(-1)))=e^(-1)=1/e}}}