Question 288074
If the vertices of the right angle triamgle ABC are A(-1,2) B(3,8) C(5,-2) use coordinate geometry to prove that point M,the midpoint of the hypotenuse is equidistant from all three vertices of the triangle.
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BC is the hypotenuse
Mx = (3+5)/2 = 4
My = (8-2)/2 = 3
Midpoint M (4,3)
M is equidistant from B and C by definition.
{{{s^2 = diffy^2 + diffx^2}}}
{{{s^2 = 1 + 5^2 = 26}}}
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Find the distance from M to A:
{{{s^2 = 5^2 + 1 = 26}}}
Same distance
QED