Question 287907
The general form for the equation of a parabola is
{{{f(x) = ax^2 + bx +c}}}
So your "a" is -2, your "b" is 2 and your "c" is 6. Use these numbers below:<br>
1.) What is the x-coordinate of the vertex?
The x-coordinate of the vertex is {{{(-b)/2a}}}<br>
2.) What is the y-coordinate of the vertex?
Put the value of {{{(-b)/2a}}} into the function for x and calculate y/f(x)<br>
3.) The equation of the line of symmetry is x= {{{(-b)/2a}}}<br>
4.) The maximum/minimum of f(x) is the: <u>vertex</u><br>
5.) The value f(1/2)=13/2 is minimum or maximum?
Since the "a" is negative, this parabola opens downward. So the vertex is a maximum value. If the point (1/2, 13/2) is the vertex, which you should know from #1 and #2 above, then it is the maximum value for f(x).