Question 287959
Hint: If {{{A(2x-3) + B(x+2) = 5x-11}}}, then {{{2Ax-3A+Bx+2B=5x-11}}} which can be rewritten as {{{(2A+B)x+(-3A+2B)=5x-11}}}



From there, notice that the 'x' "coefficient" on the left side is {{{2A+B}}} and the right 'x' coefficient is 5. Since there are no other 'x' terms, this must mean that {{{2A+B=5}}}. Using similar logic, the constant terms of {{{-3A+2B}}} on the left side match up with the constant -11 on the right. So {{{-3A+2B=-11}}}



What we now have is a system of two equations in two unknowns which are {{{system(2A+B=5,-3A+2B=-11)}}}



So just solve this system for A and B. I'll let you do that.