Question 287989
this is saying {{{x+y=66}}} and {{{(2/5)x-(5/8)y=10}}}
u have 2 equations so substitution or elimination method will work.
i will show substitution.
{{{x+y=66}}}
{{{x=66-y}}}
{{{(2/5)x-(5/8)y=10}}}
{{{(2/5)(66-y)-(5/8)y=10}}}distribute
{{{(132/5)-(2/5)y-(5/8)y=10}}}find Common denominator for like terms
{{{(132/5)-(16/40)y-(25/40)y=10}}}
{{{(132/5)-(41/40)y=10}}}
{{{(132/5)-10=(41/40)y}}}
{{{(132/5)-(50/5)=(41/40)y}}}
{{{(82/5)=(41/40)y}}}multiply by reciprical
{{{(82/5)(40/41)=y}}}
{{{(2/1)(8/1)=y}}}
{{{16=y}}}
{{{50=x}}}