<PRE><B>Question 287921</B>
If a car is traveling East going 60 miles per hour and then another car heading
 the same direction is traveling 80 miles per hour but starts 25 seconds later
 what is the distance the second car will catch the first one?
:
Convert 60 and 80 mph to ft/sec
{{{(60*5280)/3600}}} =  88 ft/sec
{{{(80*5280)/3600}}} = 117.3 ft/sec
:
Let t = travel time for 2nd car (in sec)
then
(t+25) = travel time for 1st car
:
write a dist equation: dist = speed * time
:
1st car dist = 2nd car dist
88(t + 25) = 117.3t
88t + 2200 = 117.3t
2200 = 117.3t - 88t
2200 = 29.3t
t = {{{2200/29.3}}}
t = 75.1 seconds for second car to catch the 1st car
:
Find the dist
1st car: 88(75.1+25) = 8809 ft
Both cars should travel the same distance
2nd car: 117.3(75.1) = 8809 ft
:
That is {{{8809/5280}}} = 1.67 miles

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