Question 287902
Hint: {{{t^2-64}}} factors into {{{(t+8)(t-8)}}} and {{{(t+8)^2}}} breaks down to {{{(t+8)(t+8)}}}. So {{{(t^2-64)/((t+8)^2)=((t+8)(t-8))/((t+8)(t+8))}}}