Question 34577
First thing you need to do is get rid of the fraction, thus you multiply x by each term, which gives you a quadratic equation: {{{x(x)=(x)3/x + 1(x)}}}
                                                 {{{x^2=3x/x + x}}}
                                              {{{x^2=3 + x}}}  set equal to 0
                                              {{{x^2-x-3=0}}}
This quadractic doesnt factor, so you have to 'complete the square' like this:  first isolate the variable terms to get {{{x^2-x=3}}}
      Make sure first term has coefficient of 1, it does 
      Then take coefficient of middle term (-x) and find the perfect square trinomial like this:  {{{(-1/2)^2}}} which gives you 1/4 or .25
      Just add this to both sides to {{{x^2-x+1/4=3+1/4}}} and you get                                 {{{x^2-x+1/4=13/4}}}
Now you can factor the left side of this to get {{{(x-1/2)^2=13/4}}}
Now you can solve for x using the square root method by taking square root of both sides to get {{{x-1/2 = sqrt(13/4)}}} =    {{{x-1/2=1.803}}}   {{{x = 1.803+1/2}}} 

x= 2.303   

Check 2.303 = 3/2.303 + 1    
2.303=1.303+1 yes