Question 287734
The formula  for the car is
{{{d = (1/2)*at^2}}}
where
{{{d}}} = distance traveled
{{{a}}} = acceleration from stop
{{{t}}} = elapsed time
The formula for the truck is
{{{d = vt}}}
{{{v}}} = the velocity
----------------------
given:
{{{a = 6}}} ft/sec/sec
{{{v = 30}}} ft/sec
---------------
{{{d = (1/2)*6t^2}}}
and
{{{d = 30t}}}
so,
{{{(1/2)*6t^2 = 30t}}}
{{{3t^2 = 30t}}}
{{{t = 10}}}
and
{{{d = 30t}}}
{{{d = 30*10}}}
{{{d = 300}}}
(a) the car passes the truck 300 ft from start
and
For car {{{v = a*t}}}
{{{v = 6*10}}}
{{{v = 60}}}
(b) the car's velocity is 60 ft/sec when it passes the truck