Question 287727
log(d)+log(2d+1)=log(7d)
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log(d(2d+1)) = log(7d)
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2d^2 + d = 7d
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2d^2-6d = 0
d(2d-6) = 0
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d = 0 or d = 3
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d cannot be 0 because log(7*0) does not exist.
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Only solution:
d = 3
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Cheers,
Stan H.