Question 287661

Set the right side of the equation to zero by adding 3 to both sides of the equation:

{{{x^2+7x+3=0}}}

The quadratic formula is:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


In your question

a=1
b=7
c=3

{{{x = (-7 +- sqrt( 7^2-4*1*3 ))/(2*1) }}}
{{{x = (-7 +- sqrt( 49-12 ))/(2) }}}
{{{x = (-7 +- sqrt( 37 ))/(2) }}}


To be exact, you can leave your answer like that, with the radicals. Note that you have two answers, one for the + sign and one for the - sign.


If you want to write your answers as decimals, they would be:


x=-0.4586 or x=-6.541